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BITSAT 2022
Exam
BITSAT
Year
2022
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2022 · Physics · Motion in Two Dimensions

A projectile is projected with the velocity of (3 i +4 j ) m / s ....

A projectile is projected with the velocity of (3i^+4j^)m/s(3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}. The horizontal range of the projectile will beA projectile is projected with the velocity of (3 i +4 j ) m / s . The horizontal range of the projectile will be

Options

  1. A1.2m1.2 \mathrm{ m}
  2. B2.4m2.4 \mathrm{ m}
  3. C3.6m3.6 \mathrm{ m}
  4. D4.5m4.5 \mathrm{ m}

Correct answer

B. 2.4m2.4 \mathrm{ m}

Step-by-step solution

Given, v=3i^+4j^∴v=∣v∣=32+42⇒\mathbf{v}=3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}} \therefore \quad v=|\mathrm{v}|=\sqrt{3^2+4^2} \Rightarrow v=5 m\mathrm{ m}/ s\mathrm{s} From figure, <imgsrc="/api/proxy−image?url=https<img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fbitsat%252FS68DyZBu4WVIyvgm-kVZTbqOsJd6ueHWTqIkKHSEDW4.original.fullsize.png%3Falt%3Dmedia \text{ and } clean=1 \text{ and } v=wm2" data-qx-orig-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fbitsat%2FS68DyZBu4WVIyvgm-kVZTbqOsJd6ueHWTqIkKHSEDW4.original.fullsize.png?alt=media" data-qx-storage-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fbitsat%2FS68DyZBu4WVIyvgm-kVZTbqOsJd6ueHWTqIkKHSEDW4.original.fullsize.png?alt=media"> \\ \sin \theta=\frac{4}{5} and cos⁡θ=35∵R=v2sin⁡2θg=v2⋅2sin⁡θ⋅cos⁡θg=5×5×2×45×3510=24m\cos \theta=\frac{3}{5}\because \quad R=\frac{v^2 \sin 2 \theta}{g}=\frac{v^2 \cdot 2 \sin \theta \cdot \cos \theta}{g}=\frac{5 \times 5 \times 2 \times \frac{4}{5} \times \frac{3}{5}}{10}=24 \mathrm{ m}
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