A particle executes simple harmonic motion between x=-A and x=+A . If time taken by particle to go from x=0 to A 2 is 2 s ; then time taken by particle in going from x= A 2 to A is:

Step-by-step solution

Let time from 0 to A / 2 is t ₁ and from A / 2 to A is t ₂ From the standard equation of SHM, A 2 = A ( t ₁ ) t₁= ⁻¹ ( 1 2 )= 6 ....(i) Using x=A₀ t again A=A (t₁+t₂ ) (t₁+t₂ )= ⁻¹(1)= 2 Using (i) t₂= 2 - 6 = 3 .....(ii) Dividing equation (i) by (ii) we get t₁ t₂ = 1 2 t₂=2 t₁=2 2=4 sec