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BITSAT 2021
Exam
BITSAT
Year
2021
Subject
Physics
Chapter
Oscillations

BITSAT 2021 · Physics · Oscillations

Four massless springs whose force constants are 2 k, 2 k, k and 2 k...

Four massless springs whose force constants are 2k,2k,k2 k, 2 k, k and 2k2 k respectively are attached to a mass M\mathrm{M} kept on a frictionless plane (as shown in figure). If the mass MM is displaced in the horizontal direction, then the frequency of the system is?

Options

  1. A12πk4M\frac{1}{2 \pi} \sqrt{\frac{k}{4 \mathrm{M}}}
  2. B1πkM\frac{1}{\pi} \sqrt{\frac{k}{\mathrm{M}}}
  3. C12πk7M\frac{1}{2 \pi} \sqrt{\frac{k}{7 \mathrm{M}}}
  4. D12π7kM\frac{1}{2 \pi} \sqrt{\frac{7 k}{\mathrm{M}}}

Correct answer

B. 1πkM\frac{1}{\pi} \sqrt{\frac{k}{\mathrm{M}}}

Step-by-step solution

The equivalent system is shown in figure. Four massless springs whose force constants are 2 k, 2 k, k and 2 k respectively are attached to a mass M kept on a
The equivalent force constant of which ke=k+3k=4k∴ω=kem=4km=2kmk_{\mathrm{e}}=k+3 k=4 k\therefore \omega=\sqrt{\frac{k_{e}}{m}}=\sqrt{\frac{4 k}{m}}=2 \sqrt{\frac{k}{m}} and f=ω2π=22πkm=1πkm\mathrm{f}=\frac{\omega}{2 \pi}=\frac{2}{2 \pi} \sqrt{\frac{k}{m}}=\frac{1}{\pi} \sqrt{\frac{k}{m}}
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