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BITSAT Oscillations PYQs with Solutions

31 previous year questions from Oscillations (BITSAT Physics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

31 questionsPhysics2009–2024Answers + solutions

About Oscillations PYQs

Oscillations has 31 previous year questions in the Quantrex Academy BITSAT Physics bank. The 31 questions in this list come from BITSAT (31), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

  • 2024: 3
  • 2023: 2
  • 2022: 1
  • 2021: 2
  • 2020: 3
  • 2019: 2
  • 2018: 2
  • 2017: 4
  • 2016: 2
  • 2015: 2
  • 2014: 2
  • 2013: 1

Oscillations questions with solutions

1

Five identical springs are used in the three configurations as shown in figure. The time periods of vertical oscillations in configurations (a), (b) and (c) are in the ratio.

BITSAT 2024 Solution
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2

A particle executes simple harmonic motion between x=-A and x=+A . If time taken by particle to go from x=0 to (A)/(2) is 2 s ; then time taken by particle in going from x=(A)/(2)

BITSAT 2024 Solution
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3

A simple pendulum doing small oscillations at a place R height above earth surface has time period of T_1=4 s . T_2 would be it's time period if it is brought to a point which is

BITSAT 2024 Solution
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4

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x) starting from mean position to extreme position (A) is given by

BITSAT 2023 Solution
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5

A particle executes SHM of amplitude A. The distance from the mean position when it's kinetic energy becomes equal to its potential energy is

BITSAT 2023 Solution
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6

In a resonance column first and second resonance are obtained at depths 24 cm and 78 cm the third resonance will be obtained at depth.

BITSAT 2022 Solution
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7

Four massless springs whose force constants are 2 k, 2 k, k and 2 k respectively are attached to a mass M kept on a frictionless plane (as shown in figure). If the mass M is

BITSAT 2021 Solution
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8

In a simple pendulum of length I the bob is pulled aside from its equilibrium position through an angle θ and then released. The bob passes through the equilibrium position with

BITSAT 2021 Solution
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9

Frequency of oscillation is proportional to

BITSAT 2020 Solution
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10

An instantaneous displacement of a simple harmonic oscillator is x=A (ω t+π / 4) . Its speed will be maximum at time

BITSAT 2020 Solution
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11

A particle executing simple harmonic motion along y -axis has its motion described by the equation y=A (ω t)+B . The amplitude of the simple harmonic motion is

BITSAT 2020 Solution
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12

The time period of a bob performing simple harmonic motion in water is 2s . If density of bob is (4)/(3) × 10 ^ 3 kgm^ - 3 , then time period of bob performing simple harmonic

BITSAT 2019 Solution
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13

Frequency of oscillation of a body is 5 Hz when a force F _ 1 is applied and 12 Hz when another force F _ 2 is applied. If both forces F _ 1 and F _ 2 are applied together, then

BITSAT 2019 Solution
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14

The bob of simple pendulum is a spherical hollow ball filled with water. A plugged hole near the bottom of the oscillating bob get& suddenly unplugged. During observation, till

BITSAT 2018 Solution
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15

If x, v and a denote the displacement, the velocity and the acceleration of a particle executing SHM of time period T . Then, which of the following does not change with time?

BITSAT 2018 Solution
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16

A body of mass 1 kg is executing simple harmonic motion. Its displacement y (cm) at t seconds is given by y = 6sin (100t + (π)/(4)). Its maximum kinetic energy is

BITSAT 2017 Solution
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17

A rectangular block of mass m and area of cross-section A floats in a liquid of density ρ . If it is given a vertical displacement from equilibrium, it undergoes oscillation with

BITSAT 2017 Solution
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18

A load of mass m falls from a height h on the scale pan hung from a spring as shown. If the spring constant is k and the mass of the scale pan is zero and the mass m does not

BITSAT 2017 Solution
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19

Two simple pendulums of lengths 5m and 20m respectively are given small displacement in one direction at the same time they will again be in the same sense when the pendulum of

BITSAT 2017 Solution
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20

A 1 ~kg mass is attached to a spring of force constant 600 ~N / m and rests on a smooth horizontal surface with other end of the spring tied to wall as shown in figure. A second

BITSAT 2016 Solution
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21

A point particle of mass 0.1 ~kg is executing S.H.M. of amplitude of 0.1 ~m . When the particle passes through the mean position, its kinetic energy is 8 × 10^ -3 Joule. Obtain

BITSAT 2016 Solution
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22

The displacement of a particle is given at time t, by: x=A (-2 ω t)+B ^ 2 ω t Then,

BITSAT 2015 Solution
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23

Vertical displacement of a plank with a body of mass \(m\) on it is varying according to law \(y= ω t+ 3 \). The minimum value of \(ω\) for which the mass just breaks off the

BITSAT 2015 Solution
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24

Two particles P and Q describe S.H.M. of same amplitude a, same frequency f along the same straight line. The maximum distance between the two particles is a 2 . The initial phase

BITSAT 2014 Solution
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25

A tunnel has been dug through the centre of the earth and a ball is released in it. It executes S.H.M. with time period

BITSAT 2014 Solution
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26

An instantaneous displacement of a simple harmonic oscillator is x=A (ω t+π / 4). Its speed will be maximum at time

BITSAT 2013 Solution
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27

Which of the following expressions corresponds to simple harmonic motion along a straight line, where x is the displacement and a, b, c are positive constants?

BITSAT 2011 Solution
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28

A mass m is suspended from a spring of force constant k and just touches another identical spring fixed to the floor as shown in the figure. The time period of small oscillations

BITSAT 2011 Solution
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29

A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration 3 ms^ -2 is

BITSAT 2010 Solution
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30

In case of a forced vibration, the resonance wave becomes very sharp when the

BITSAT 2009 Solution
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31

A pendulum bob carries a +ve charge +q. A positive charge +q is held at the point of support. Then the time period of the bob is [where, L= length of pendulum, g_ eff = effective

BITSAT 2009 Solution
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