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BITSAT2010PhysicsRay OpticsActual

The diameter of the objective of a telescope is a, its magnifying power is m and wavelength of light is , The resolving power of the telescope is:

Options

  1. A(1.22 ) / a
  2. B(1.22 a ) /
  3. Cm /(1.22 a )
  4. Da/(1.22 )

Correct answer

D. a/(1.22 )

Step-by-step solution

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