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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Physics
Chapter
Ray Optics

BITSAT 2010 · Physics · Ray Optics

The diameter of the objective of a telescope is a, its magnifying...

The diameter of the objective of a telescope is a, its magnifying power is m\mathrm{m} and wavelength of light is λ,\lambda, The resolving power of the telescope is:

Options

  1. A(1.22λ)/a(1.22 \lambda) / \mathrm{a}
  2. B(1.22a)/λ(1.22 \mathrm{a}) / \lambda
  3. Cλm/(1.22a)\lambda \mathrm{m} /(1.22 \mathrm{a})
  4. Da/(1.22\lambda)

Correct answer

D. a/(1.22\lambda)

Step-by-step solution

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