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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Physics
Chapter
Semiconductors

BITSAT 2013 · Physics · Semiconductors

The circuit is equivalent to

The circuit is equivalent to The circuit is equivalent to

Options

  1. AAND gate
  2. BOR gate
  3. CNot gate
  4. DNone of these

Correct answer

B. OR gate

Step-by-step solution

Y=A+(A‾⋅B)=(A+A‾)⋅(A+B)=A+B⇒OR gate \begin{aligned} \mathrm{Y} &=\mathrm{A}+(\overline{\mathrm{A}} \cdot \mathrm{B})=(\mathrm{A}+\overline{\mathrm{A}}) \cdot(\mathrm{A}+\mathrm{B}) \\ &=\mathrm{A}+\mathrm{B} \\ \Rightarrow & \mathrm{OR} \text{ gate } \end{aligned}
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