Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Physics
Chapter
Thermodynamics

BITSAT 2013 · Physics · Thermodynamics

A vessel containing 1 more of O_ 2 gas (molar mass 32) at...

A vessel containing 1 more of O2\mathrm{O}_{2} gas (molar mass 32) at temperature T\mathrm{T}. The pressure of the gas is p. An identical vessel containing one mole of he gas (molar mass 4 ) at temperature 2T2 \mathrm{ T} has a pressure of

Options

  1. Ap/8\mathrm{p} / 8
  2. Bp\mathrm{p}
  3. C2p2 \mathrm{p}
  4. D8p8 \mathrm{p}

Correct answer

C. 2p2 \mathrm{p}

Step-by-step solution

Applying gas equation, pV=nRT\mathrm{pV}=\mathrm{nRT} We can write, p1V=n1RT1\mathrm{p}_{1} \mathrm{ V}=\mathrm{n}_{1} \mathrm{RT}_{1} and p2V=n2RT2⇒p2p1=n2n1×T2T1=11×2TT=2⇒p2=2p\mathrm{p}_{2} \mathrm{ V}=\mathrm{n}_{2} \mathrm{RT}_{2}\Rightarrow \quad \frac{\mathrm{p}_{2}}{\mathrm{p}_{1}}=\frac{\mathrm{n}_{2}}{\mathrm{n}_{1}} \times \frac{\mathrm{T}_{2}}{\mathrm{ T}_{1}}=\frac{1}{1} \times \frac{2 \mathrm{ T}}{\mathrm{ T}}=2\Rightarrow \mathrm{p}_{2}=2 \mathrm{p}
Practice Thermodynamics on Quantrex Academy →

More from Thermodynamics

In the given cycle A B C D A , the heat required for an ideal monoatomic gas will be BITSAT 2024A gas can be taken from A to B via two different processes A C B and A D B . When path A… BITSAT 2024A source supplies heat to a system at the rate of 1000 W. If the system performs work at… BITSAT 2024On celcius scale the temperature of body increases by 40^ ^ ∘ C . The increase in… BITSAT 2024A hypothetical gas expands adiabatically such that its volume changes from 08 litres to… BITSAT 2023A thermodynamic system is taken through cyclic process. The total work done in the… BITSAT 2023An ideal gas at atmospheric pressure is adiabatically compressed so that its density… BITSAT 2021The compressibility of water is 4 × 10^ -5 per unit atmospheric pressure. The decrease in… BITSAT 2021 Full Thermodynamics list All BITSAT PYQs