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BITSAT 2009
Exam
BITSAT
Year
2009
Subject
Physics
Chapter
Thermodynamics

BITSAT 2009 · Physics · Thermodynamics

A cyclic process is shown in the p-T diagram. Which of the curves...

A cyclic process is shown in the p-T diagram. Which of the curves show the same process on a P\mathrm{P} - V\mathrm{V} diagram? A cyclic process is shown in the p-T diagram. Which of the curves show the same process on a P - V diagram?

Options

  1. ALet ABC be an isosceles triangle with AB=BC . A trisector of B meets AC at D . If AB, AC and B D are integers and A B-B
  2. BLet ABC be an isosceles triangle with AB=BC . A trisector of B meets AC at D . If AB, AC and B D are integers and A B-B
  3. CLet ABC be an isosceles triangle with AB=BC . A trisector of B meets AC at D . If AB, AC and B D are integers and A B-B
  4. DLet ABC be an isosceles triangle with AB=BC . A trisector of B meets AC at D . If AB, AC and B D are integers and A B-B

Correct answer

B. Let ABC be an isosceles triangle with AB=BC . A trisector of B meets AC at D . If AB, AC and B D are integers and A B-B

Step-by-step solution

- Given diagram: P-T graph. - Using ideal gas law: (P V=n R T \Rightarrow V=nRTP\frac{n R T}{P}. So in a P−TP-T graph we can infer how VV behaves. Step analysis of cycle (A→B→C→A\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{A} : - A (→B:Both\rightarrow \mathrm{B}: BothP$andandTincreaseproportionally(straightlinethroughorigin).(⇒V=nRTP= constant. increase proportionally (straight line through origin). (\Rightarrow V=\frac{n R T}{P}=\text{ constant. } So (A\mathrm{A} \rightarrow B\mathrm{B} is an isochoric process in P−VP-V. - (B\mathrm{B} \rightarrow C\mathrm{C}: T) constant, PP decreases. (\Rightarrow) Isothermal expansionininP-V.−(C→A:P)constant,. - (\mathrm{C} \rightarrow\mathrm{A}: P) constant,Tdecreases.(⇒)Isochoricprocessindecreases. (\Rightarrow) Isochoric process inP-V$. So the cycle consists of: - Isochoric line, - Isothermal curve, - Isochoric line. This matches diagram (2).
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