Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2018PhysicsWave OpticsActual

In Young's double slit experiment, intensity at a point is 1 4 of the maximum intensity. Angular position of this point is

Options

  1. Asin - 1 λ d
  2. Bsin - 1 λ 2 d
  3. Csin - 1 λ 3 d
  4. Dsin - 1 λ 4 d

Correct answer

C. sin - 1 λ 3 d

Step-by-step solution

I = I max cos 2 ϕ 2 I max 4 = I max cos 2 ϕ 2 cos ϕ 2 = 1 2 ϕ 2 = π 3 ⇒   ϕ = 2 π 3 = 2 π λ × Δ x . . . . i where, Δ x = d sin θ Putting the value of Δ x in Eq. (i), we get sin θ = λ 3 d θ = sin - 1 λ 3 d

Practice Wave Optics on Quantrex Academy →

More from Wave Optics

Young's double slit experiment is performed in a medium of refractive index of 1.33 . The maximum intensity is I₀ . The intensity at a point on the screen, where path difference be 2024In YDSE, monochromatic light falls on a screen 1.80 m from two slits separated by 2.08 mm . The first and second order bright fringes are separated by 0.553 mm . The wavelength of 2024A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm . The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from 2024The property of light which cannot be explained by Huygen's construction of wavefront is 2024When a light ray incidents on the surface of a medium, the reflected ray is completely polarized. Then the angle between reflected and refracted rays is 2024A single slit of a width a is illuminated by a monochromatic light of wavelength 600 ~nm . The value of ' a ' for which first minimum appears at =30^ on the screen will be : 2023The ratio of intensities at two points P and Q on the screen in a Young's double slit experiment where phase difference between two wave of same amplitude are 3 and 2 , respectivel 2023In a Young's double slit experiment, the intensities at two points, for the path difference 4 and 3 ( being the wavelength of light used) are I₁ and I₂ respectively. If I₀ denotes 2023 Full Wave Optics list All BITSAT PYQs