BITSAT2015PhysicsWave OpticsActual
Calculate the wavelength of light used in an interference experiment from the following data: Fringe width =0.03 ~cm . Distance between the slits and eyepiece through which the interference pattern is observed is 1 ~m . Distance between the images of the virtual source when a convex lens of focal length 16 ~cm is used at a distance of 80 ~cm from the eyepiece is 0.8 ~cm .
Options
- A0.0006 Ã…
- B0.0006 ~m
- C600 ~cm
- D6000 Ã…
Correct answer
D. 6000 Ã…
Step-by-step solution
Given: fringe with =0.03 ~cm , D =1 ~m =100 cm Distance between images of the source =0.8 ~cm . Image distance v=80 ~cm Object distance =u Using mirror formula, array l array l 1 v + 1 u = 1 f 1 60 + 1 u = 1 16 u =20 ~cm array Magnification, m = v u = 80 20 =4 Magnification aligned distances between images of slits distance between slits = 0.8 ~d = 0.8 ~d =4 d =0.2 ~cm aligned Fringe width = D d array or, = 100 0.2 =0.03 10⁻² Therefore, wavelength of light used =6000Ã…