A transverse wave propagating on a stretched string of linear...

Equation of wave,&

$y = 0. 2sin [ 1. 5x + 60t ]$

Comparing with standard equation, we get

$y = Asin [ kx + \omegat ]$

$k = 1. 5 = \dfrac{2\pi}{λ}$

and $\omega = 60 = \dfrac{2\pi}{T}$

$∴$ Velocity of wave, $v = \dfrac{ω}{k}$

$= \dfrac{60}{1. 5} = 40ms^{- 1}$

Velocity of wave in stretched string, $v = \sqrt{\dfrac{T}{m}}$

where, $m$ is the linear density, $T$ is tension in the string.

So, $T = v^{2}m = ( 40{)}^{2} \times 3 \times {10}^{- 4}$

$= 0. 48N$