For a given reaction of the type 3 5 X(a q) 1 2 Y(a q)+Z(g) , the correct expression for the rate of disappearance of X with reference to Y is

Step-by-step solution

For a general chemical reaction aA + bB cC + dD , the rate of reaction is given by - 1 a d[A] dt = - 1 b d[B] dt = 1 c d[C] dt = 1 d d[D] dt . Given the reaction 3 5 X 1 2 Y + Z , we apply the rate expression: - 1 3/5 d[X] dt = 1 1/2 d[Y] dt - 5 3 d[X] dt = 2 d[Y] dt Rearranging to solve for the rate of disappearance of X , which is - d[X] dt : - d[X] dt = 3 5 2 d[Y] dt - d[X] dt = 6 5 d[Y] dt Answer: -d [X] d t =+ 6 5 d [Y] d t