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A given chemical reaction is represented by the following stoichiometric equation. 3 X+2 Y+ 5 2 Z P₁+P₂+P₃ The rate of reaction can be expressed as _________.

Options

  1. A( d[X] d t )= 3 2 ( d[Y] d t )= 15 4 ( d[Z] d t )
  2. B2 3 ( d[X] d t )= ( d[Y] d t )= 4 5 ( d[Z] d t )
  3. C4 15 ( d[X] d t )= 4 5 ( d[Y] d t )= 8 15 ( d[Z] d t )
  4. D3 2 ( d[X] d t )= 1 4 ( d[Y] d t )= 8 5 ( d[Z] d t )

Correct answer

B. 2 3 ( d[X] d t )= ( d[Y] d t )= 4 5 ( d[Z] d t )

Step-by-step solution

For a general reaction aA + bB + cC Products , the rate of reaction is given by: Rate = - 1 a d[A] dt = - 1 b d[B] dt = - 1 c d[C] dt Given the reaction 3X + 2Y + 5 2 Z P₁ + P₂ + P₃ , the rate of reaction is: Rate = - 1 3 d[X] dt = - 1 2 d[Y] dt = - 1 5/2 d[Z] dt = - 2 5 d[Z] dt Equating the terms: - 1 3 d[X] dt = - 1 2 d[Y] dt 2 3 d[X] dt = d[Y] dt - 1 2 d[Y] dt = - 2 5 d[Z] dt d[Y] dt = 4 5 d[Z] dt Combining these, we get: 2 3 d[X] dt = d[Y] dt = 4 5 d[Z] dt Answer: 2 3 ( d[X] d t )= ( d[Y] d t )= 4 5 ( d[Z] d t

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