At 300 ~K , the half-life period of a gaseous reaction at an initial pressure of 40 kPa is 350 s. When pressure is 20 kPa , the half-life period is 175 ~s . What is the order of the reaction?

Step-by-step solution

We know that (t_ 1 / 2 )₁ (t_ 1 / 2 )₂ = ( p₂ p₁ )^ n-1 where, n is the order of reaction and t_ 1 / 2 is half-life. gathered 350 175 = ( 20 40 )^ n-1 2= ( 1 2 )^ n-1 n-1=-1 n=0 gathered It is a zero order reaction.