The wavelength absorbed by the complex [Cu(H₂O)₄]²⁺ (assuming tetrahedral geometry) for the d-d transition is 600 nm. The crystal field splitting energy for the complex [Cu(H₂O)₆]²⁺ is: [Given: h = 6.626 10⁻³⁴ Js , c = 3 10^8 ms ⁻¹ , and 1

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The wavelength absorbed by the complex [Cu(H₂O)₄]²⁺ (assuming tetrahedral geometry) for the d-d transition is 600 nm. The crystal field splitting energy for the complex [Cu(H₂O)₆]²⁺ is: [Given: h = 6.626 10⁻³⁴ Js , c = 3 10^8 ms ⁻¹ , and 1 eV = 1.6 10⁻¹⁹ J ]

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Correct answer: B. 4.7 eV

Tetrahedral splitting energy: _t = hc = (6.626 10⁻³⁴)(3 10^8) 600 10⁻⁹ = 3.313 10⁻¹⁹ J Since _t = 4 9 _o : _o = 9 4 3.313 10⁻¹⁹ = 7.454 10⁻¹⁹ J Converting to eV: _o = 7.454 10⁻¹⁹ 1.6 10⁻¹⁹ 4.7 eV

The wavelength absorbed by the complex [Cu(H₂O)₄]²⁺ (assuming tetrahedral geometry) for the d-d transition is 600 nm. The crystal field splitting energy for the complex [Cu(H₂O)₆]²⁺ is: [Given: h = 6.626 10⁻³⁴ Js , c = 3 10^8 ms ⁻¹ , and 1 eV = 1.6 10⁻¹⁹ J ]

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