COMEDK202510 May 2025Morning ShiftChemistryCoordination CompoundsActual
An aqueous solution of CrCl ₃ .6 H ₂ O (Molar mass =266.5 ~g / mol ) containing 2.665 g of the solute after processing, when treated with excess of AgNO ₃ gave 2.87 g of AgCl (Molar mass of AgCl =143.5 ~g / mol ) Choose the correct formula of the compound which give these results.
Options
- A[ Cr ( H ₂ O )₃ Cl ₃ ] 3 H ₂ O
- B[ Cr ( H ₂ O )₅ Cl ] Cl ₂ H ₂ O
- C[ Cr ( H ₂ O )₄ Cl ₂ ] Cl .2 H ₂ O
- D[ Cr ( H ₂ O )₆ ] Cl ₃
Correct answer
B. [ Cr ( H ₂ O )₅ Cl ] Cl ₂ H ₂ O
Step-by-step solution
The number of moles of the complex CrCl ₃ 6 H ₂ O is calculated as: Moles of complex = 2.665 g 266.5 g/mol = 0.01 mol . The number of moles of AgCl precipitated is calculated as: Moles of AgCl = 2.87 g 143.5 g/mol = 0.02 mol . The reaction with AgNO ₃ precipitates only the chloride ions present outside the coordination sphere. Let x be the number of ionizable chloride ions per mole of the complex. The stoichiometry of the reaction is: Moles of AgCl = x Moles of complex 0.02 = x 0.01 x = 2 . Since there are 2 ioniza