In alkaline medium, I⁻ is oxidised to ' X ' by KMnO ₄ . The oxidation state of iodine in ' X ' is:

Step-by-step solution

In alkaline medium, the reaction between permanganate ion and iodide ion is given by the balanced chemical equation: 2MnO₄⁻ + I ⁻ + H₂ O 2MnO₂ + IO₃⁻ + 2OH ⁻ The product 'X' formed by the oxidation of I ⁻ is the iodate ion, IO₃⁻ . To find the oxidation state of iodine in IO₃⁻ , let the oxidation state be x . x + 3(-2) = -1 x - 6 = -1 x = +5 Therefore, the oxidation state of iodine in 'X' is +5. Answer: +5