A current of 0.10 A was passed for 2 hours through a dilute solution of sulphuric acid. The total volume of gaseous products produced at STP is: [Given: 1 ~F =96500 C ; Molar volume at STP is 22.7 ~mol ⁻¹ ]

Step-by-step solution

The electrolysis of dilute sulphuric acid involves the electrolysis of water. The reactions at the electrodes are as follows: At cathode: 4H⁺(aq) + 4e⁻ 2H₂(g) At anode: 2H₂O(l) O₂(g) + 4H⁺(aq) + 4e⁻ The total charge passed Q is given by Q = I t = 0.10 A (2 3600 s ) = 720 C . The number of moles of electrons passed is n_ e = Q F = 720 96500 0.00746 mol . From the stoichiometry, 4 moles of electrons produce 2 moles of H₂ and 1 mole of O₂ , totaling 3 moles of gas. Thus, 4 moles of electrons produce 3 moles of gas. To