For the cell reaction 4 Br ⁻+ O ₂+4 H ⁺ 2 Br ₂+2 H ₂ O at 298 K , the E ^0 cell =0.16 ~V . What would be the K _ c (Equilibrium constant) value if the reverse reaction were to take place?

Step-by-step solution

For the reverse reaction, E°_ rev = -0.16 V and n = 4 . Using E° = 0.059 n K_c : -0.16 = 0.059 4 K_c K_c = -0.16 4 0.059 = -0.64 0.059 -10.847 K_c = 10^ -10.847 1.422 10⁻¹¹