3 Faraday of electricity is passed through three electrolytic cells connected in series containing Ag ⁺, Ca ²⁺ and Al ⁺³ ions respectively. The molar ratio in which the 3 metal ions are liberated at the electrodes is

Step-by-step solution

array r Ag ⁺+e⁻ Ag Ca ⁺²+2 e⁻ Ca Al ⁺³+3 e⁻ Al array For 1 mol of Ag ⁺, Ca ⁺² and Al ⁺³, 1 ~mol of e⁻, 2 ~mol of e⁻ and 3 mol of e⁻ are required respectively. For 1 mole e⁻=1 Faraday 1 mole of Ag ⁺ For 1 mole e⁻=1 Faraday 1 2 mole of Ca ⁺² For 1 mole e⁻=1 Faraday 1 3 mole of Al ⁺³ So, for 3 Faraday 1 3, 1 2 3, 1 3 3 =3: 3 2 : 1 or 6: 3: 2