COMEDK2022ChemistryElectrochemistry
Calculate the molar conductance of 0.025 M aqueous solution of calcium chloride at 25^ C . The specific conductance of calcium chloride is 12.04 10⁻² Sm ⁻¹
Options
- A4.816 10⁻⁵ Sm ^2 ~mol ⁻¹
- B3.816 10⁻⁵ Sm ^2 ~mol ⁻¹
- C381.6 10⁻⁵ Sm ^2 ~mol ⁻¹
- D481.6 10⁻⁵ Sm ^2 ~mol ⁻¹
Correct answer
D. 481.6 10⁻⁵ Sm ^2 ~mol ⁻¹
Step-by-step solution
The molar conductance _m is given by the formula _m = C , where is the specific conductance and C is the molar concentration. Given: = 12.04 10⁻² S m ⁻¹ C = 0.025 M = 0.025 mol L ⁻¹ Convert concentration to mol m ⁻³ : 1 L = 10⁻³ m ^3 C = 0.025 mol / 10⁻³ m ^3 = 25 mol m ⁻³ Substitute the values into the formula: _m = 12.04 10⁻² S m ⁻¹ 25 mol m ⁻³ _m = 0.4816 10⁻² S m ^2 mol ⁻¹ Express in scientific notation as required by the options: _m = 481.6 10⁻⁵ S m ^2 mol ⁻¹ Answer: 481.6 10⁻⁵ Sm ^2 ~mol ⁻¹