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When the same amount of electricity is passed through solutions of silver nitrate and copper sulphate, 0.4 ~g copper is deposite(d)The amount of silver deposited is

Options

  1. A1.35 ~g
  2. B2.7 ~g
  3. C5.1 ~g
  4. D5.4 ~g

Correct answer

A. 1.35 ~g

Step-by-step solution

According to Faraday's second law, w₁ E₁ = w₂ E₂ where, w and E are mass and equivalent weight respectively. 0.4 63.5 2 = w₂ 108 w₂=1.35 ~g

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