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COMEDK2018ChemistryElectrochemistry

When a quantity of electricity is passed through CuSO ₄ solution, 0.16 ~g of copper gets deposite(d)If the same quantity of electricity is passed through acidulated water, then the volume of H ₂ liberated at STP will be [Given, atomic weight of Cu =64 ]

Options

  1. A4.0 ~cm ³
  2. B56 ~cm ³
  3. C604 ~cm ³
  4. D8.0 ~cm ³

Correct answer

B. 56 ~cm ³

Step-by-step solution

According to second law of Faraday, aligned w₁ E₁ &= w₂ E₂ 0.16 64 &= w₂ 2 w₂ &= 0.16 2 64 = 0.01 2 =0.005 ~g aligned Volume of H ₂= 0.005 2 22.400 ~cm ³= 22.4 4 =56 ~cm ³ ##0

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