COMEDK2014ChemistryElectrochemistry
The molar conductivities of NaOH , NaCl and BaCl ₂ at infinite dilution are 2.481 10⁻² ~S ~m ² ~mol ⁻¹1.265 10⁻² ~S ~m ² ~mol ⁻¹ and 2.800 10⁻² ~S ~m ² ~mol ⁻¹ respectively. The molar conductivity of Ba ( OH )₂ at infinite dilution will be
Options
- A5.232 10⁻² ~S ~m ² ~mol ⁻¹
- B9.654 10⁻² ~S ~m ² ~mol ⁻¹
- C4.016 10⁻² ~S ~m ² ~mol ⁻¹
- D1.145 10⁻² ~S ~m ² ~mol ⁻¹
Correct answer
A. 5.232 10⁻² ~S ~m ² ~mol ⁻¹
Step-by-step solution
_ m ⁰ [ Ba ( OH )₂ ]= _ m ^ ( BaCl ₂ )+2 _ m ^ ( NaOH )-2 _ m ^ ( NaCl ) . =(2.8+2 2.481-2 1.265) 10⁻² Sm ² ~mol ⁻¹=(2.8+4.962-2.53) 10⁻² ~S ~m ² ~mol ⁻¹=5.232 10⁻² ~S ~m ² ~mol ⁻¹