Same amount of electric current is passed through solutions of AgNO ₃ and HCl . If 1.08 ~g of silver is obtained in the first case, the amount of hydrogen liberated at STP in the second case is

Step-by-step solution

If current is same then, aligned &E_ wt of Ag =E_ w of H ₂ & 1.08 108 = x 1 & Mass of H ₂, x=10⁻² ~g & 2 ~g of H ₂ at STP occupy 22400 ~cm ³ & 10⁻² ~g of H ₂ at STP occupy & = 22400 2 10⁻² ~cm ³=112 ~cm ³ aligned