20 g of N ₂ is made to react with 5 g of H ₂ to give ammonia. The limiting reagent and number of moles of NH ₃ formed respectively are:

Step-by-step solution

The balanced chemical equation for the formation of ammonia is: N ₂(g) + 3 H ₂(g) 2 NH ₃(g) . Calculate the initial moles of reactants: Moles of N ₂ = 20 g 28 g/mol = 0.714 moles . Moles of H ₂ = 5 g 2 g/mol = 2.5 moles . Determine the limiting reagent: According to the stoichiometry, 1 mole of N ₂ requires 3 moles of H ₂ . For 0.714 moles of N ₂ , the required H ₂ = 0.714 3 = 2.142 moles . Since the available H ₂ (2.5 moles) is greater than the required amount (2.142 moles), N ₂ is the limiting reagent. Calculate