If X is a haloalkane with a single Chlorine atom per molecule and the percentage of Cl is 55 , what would be the number of Cl atoms present in 0.1 g of the haloalkane? Atomic mass of Cl =35.5 ~g / mol

Step-by-step solution

Let the molar mass of the haloalkane be M g/mol. The percentage of Chlorine is given as 55 % . Since there is one Chlorine atom per molecule, the mass of Chlorine in one mole of the haloalkane is 35.5 g. Therefore, 35.5 M 100 = 55 . M = 35.5 100 55 = 3550 55 64.545 g/mol. The number of moles of the haloalkane in 0.1 g is n = 0.1 64.545 0.001549 moles. Since each molecule contains one Chlorine atom, the number of moles of Chlorine atoms is equal to the number of moles of the haloalkane, which is 0.001549 moles. The