An aqueous KCl solution of density 1.20 ~g / mL has a molality of 6.60 ~mol / kg . The molarity of solution in mol / L is .... (Nearest integer) [Molar mass of KCl =74.5 ]

Step-by-step solution

Given, Density of KCl solution =1.20 ~g / mL Molality of solution =6.60 ~mol / kg Molar mass of KCl =74.5 Molality = 6.60 ~mol ~kg = 6.60 ~mol solute 1000 ~g solvant aligned Mass of solution & =6.6 74.5+1000 & =1491.7 ~g aligned Volume of solution = Mass Density = 1491.7 1.20 aligned So, molarity & = 6.60 1.2 1491.7 1000 M & =5.3 ~mol / L aligned Nearest integer =5 ~mol / L