In a closed vessel, 5 moles of A₂(g) and 7 moles of B₂(g) are reacted in following manner. A₂(g)+3 B₂(g) 2 A B₃(g) What is the total number of moles of the gases present in the container at the end of the reaction?

Step-by-step solution

Thus 1 mole of A₂ react with 3 mole of B₂ 7 moles of B₂ will react with A₂= 7 3 moles A₂ left =5- 7 3 = 8 3 moles 1 mole of A₂ produces 2 moles of A B₃ 7 3 moles of A₂ will produce A B₃= 7 3 2= 14 3 moles Total moles of gases in vessel = 8 3 moles of A₂+ 14 3 moles of A B₃= 22 3 moles