When 1 mole of O ₂ and 1 mole of ammonia are made to react in the reaction, 4 NH ₃( ~g )+5 O ₂( ~g ) 4 NO ( g )+6 H ₂ O ( g )

Step-by-step solution

The balanced chemical equation is 4 NH ₃(g) + 5 O ₂(g) 4 NO (g) + 6 H ₂ O (g) . Given initial moles are n( NH ₃) = 1 mole and n( O ₂) = 1 mole. To find the limiting reagent, calculate the ratio of moles to stoichiometric coefficients: For NH ₃ : 1 4 = 0.25 For O ₂ : 1 5 = 0.20 Since 0.20 Using the stoichiometry of the reaction, 5 moles of O ₂ produce 4 moles of NO and 6 moles of H ₂ O . Therefore, 1 mole of O ₂ produces: n( NO ) = 4 5 1 = 0.8 moles of NO . n( H ₂ O ) = 6 5 1 = 1.2 moles of H ₂ O . Answer: Oxygen is