What mass of Silver chloride, in grams, gets precipitated when 150 ~ml of 32 % solution of Silver nitrate is reacted with 150 ml of 11 % Sodium chloride solution? Atomic mass in g / mol : Ag =108, Na =23, Cl =35.5, ~N =14, O =16

Step-by-step solution

The chemical reaction is: AgNO₃ + NaCl AgCl + NaNO₃ . Molar mass of AgNO₃ = 108 + 14 + 3 16 = 170 g/mol . Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol . Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol . Assuming the density of the solutions is approximately 1 g/ml , the mass of 150 ml solution is 150 g . Mass of AgNO₃ = 32 % of 150 g = 0.32 150 = 48 g . Moles of AgNO₃ = 48 170 0.2824 mol . Mass of NaCl = 11 % of 150 g = 0.11 150 = 16.5 g . Moles of NaCl = 16.5 58.5 0.2821 mol . Since the stoichiometry is 1:1 , NaCl is