15 ~g of CaCO ₃ completely reacts with

Step-by-step solution

The balanced chemical equation for the reaction between calcium carbonate and hydrochloric acid is: CaCO ₃ + 2 HCl CaCl ₂ + H ₂ O + CO ₂ The molar mass of CaCO ₃ is 40 + 12 + 3 16 = 100 g/mol . The number of moles of CaCO ₃ is 15 g 100 g/mol = 0.15 mol . According to the stoichiometry of the reaction, 1 mole of CaCO ₃ reacts with 2 moles of HCl . Therefore, 0.15 moles of CaCO ₃ will react with 0.15 2 = 0.30 moles of HCl . The molar mass of HCl is 1 + 35.5 = 36.5 g/mol . The mass of HCl required is 0.30 mol 36.5 g/m