The decomposition of a certain mass of CaCO ₃ gave 11.2 dm ³ of CO ₂ gas at STP . The mass of KOH required to completely neutralise the gas is

Step-by-step solution

Decomposition of CaCO ₃ as follows: Neutralisation reaction of KOH and CO ₂ as follows: 2 KOH + CO ₂ K ₂ CO ₃+ H ₂ O 2 moles 1 mole 1 mole 1 2 mole array ll & 60-30=10 ₁₀ I₂ I₁ & 3= ₁₀ I₂ I₁ & I₂ I₁ =10³ I₂=1000 I₁ array 1 mole of CO ₂ reacts with 2 moles of KOH 1 / 2 mole of CO ₂ reacts with 1 mole of KOH Mass of KOH =1 56.1=56.1 ~g 56 ~g