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COMEDK2012ChemistrySome Basic Concepts of Chemistry

The volume of CO ₂ ( in cm ³ ) liberated at STP, when 1.06 ~g of anhydrous sodium carbonate is treated with excess of dilute HCl is [atomic mass of Na =23]

Options

  1. A112
  2. B224
  3. C56
  4. D2240

Correct answer

B. 224

Step-by-step solution

Na ₂ CO ₃+2 HCl (dil.) 2 NaCl + CO ₂+ H ₂ O 1 ~mol (dil.) 1 ~mol =1.06 ~g =22400 ~cm ³1.06 ~g Na ₂ CO ₃ gives =22400 ~cm ³ of CO₂ 1.06 g gives = 1.06 22400 106 =224 ~cm ³ of CO ₂

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