The ratio of the number of turns of the primary coil to the secondary coil of an ideal transformer is 5: 1 . The primary is connected to 220 V supply. What is the output power of the transformer if the output resistance is 11 ?

Step-by-step solution

For an ideal transformer, the relation between the primary voltage V_p , secondary voltage V_s , and the number of turns N_p and N_s is given by V_s V_p = N_s N_p . Given N_p N_s = 5 1 , we have N_s N_p = 1 5 . Given V_p = 220 V, the secondary voltage is V_s = V_p N_s N_p = 220 1 5 = 44 V. The output power P_s is given by P_s = V_s^2 R_s , where R_s = 11 is the output resistance. Substituting the values, P_s = 44^2 11 = 1936 11 = 176 W. Answer: 176 W