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COMEDK202510 May 2025Morning ShiftPhysicsAlternating CurrentActual

An ideal inductor is connected across a capacitor. Oscillations of energy K are set up in the circuit. The capacitor plates are slowly drawn apart such that the frequency of oscillations is quadrupled. The work done in the process is

Options

  1. Azero
  2. B2 K
  3. C15 K
  4. D13 K

Correct answer

C. 15 K

Step-by-step solution

The energy stored in an LC circuit is K = 1 2 q^2 C = 1 2 LI^2 . The frequency of oscillation is f = 1 2 LC . Given that the frequency is quadrupled, f' = 4f . Since L is constant, 1 C' = 4 1 C , which implies C = 4 C' , or C' = C 16 . The energy stored in the capacitor is K = q^2 2C . Since the plates are drawn apart slowly, the charge q on the capacitor remains constant. The new energy K' is K' = q^2 2C' = q^2 2(C/16) = 16 ( q^2 2C ) = 16K . The work done by the external agent is equal to the change in the energy

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