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COMEDK202510 May 2025Morning ShiftPhysicsAlternating CurrentActual

A bulb of resistance 280 Ohm is supplied with a voltage V =400 t . The peak current is

Options

  1. A2.02 A
  2. B2.22 A
  3. C1.43 A
  4. D1.11 A

Correct answer

C. 1.43 A

Step-by-step solution

The given voltage is V = 400 ( t) . Comparing this with the standard form V = V_ peak ( t) , the peak voltage is V_ peak = 400 V. The resistance of the bulb is R = 280 Ohm. Using Ohm's law for the peak values, the peak current I_ peak is given by I_ peak = V_ peak R . I_ peak = 400 280 = 40 28 = 10 7 A. I_ peak 1.4285 A. Rounding to two decimal places, I_ peak 1.43 A. Answer: 1.43 A

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