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COMEDK2024PhysicsAlternating Current

Output of an A C source is V=100 100 t 100 t . Which of these are correct?

Options

  1. APeak voltage of source is 100 V
  2. BPeak voltage of source is 50 2 ~V
  3. CPeak voltage of source is 50 V
  4. DFrequency of the source is 50 Hz

Correct answer

C. Peak voltage of source is 50 V

Step-by-step solution

The given output voltage can be written as aligned V=100 & 100 t 100 t & =50 2 100 t 100 t & =50 2(100 t) [ 2 A A= 2 A] & =50 200 t aligned Peak voltage of given AC source, V₀=50 ~V Angular frequency, aligned & w=2 f=200 & f= 200 2 =100 ~Hz aligned

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