A coil of inductance 1 H and resistance 100 is connected to an alternating current source of frequency 50 ~Hz . What will be the phase difference between the current and voltage?

Step-by-step solution

Given inductance L = 1 H , resistance R = 100 , and frequency f = 50 Hz . The angular frequency is given by = 2 f = 2 50 = 100 rad/s . The inductive reactance X_L is given by X_L = L = 100 1 = 100 . The phase difference between the current and voltage in an LR circuit is given by = X_L R . Substituting the values, = 100 100 = 1 . Therefore, = ⁻¹(1) = 45^ . Answer: 45 ^