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COMEDK2021PhysicsAlternating Current

What should be the value of self-inductance of an inductor that should be connected to 220 ~V 50 ~Hz supply, so that a maximum current of 0.9 A flows through it?

Options

  1. A11 H
  2. B2 H
  3. C1.1 H
  4. D5 H

Correct answer

C. 1.1 H

Step-by-step solution

The given supply voltage is V_ rms = 220 V and frequency f = 50 Hz . The maximum current is I_ max = 0.9 A . The peak voltage V_ max is given by V_ max = V_ rms 2 = 220 2 V . The inductive reactance X_L is given by X_L = V_ max I_ max = 220 2 0.9 220 1.414 0.9 345.64 . The inductive reactance is also defined as X_L = 2 f L . Substituting the values, 345.64 = 2 3.14 50 L . 345.64 = 314 L . L = 345.64 314 1.1 H . Answer: 1.1 H

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