Quality factor of a series L-C-R circuit decreases from 3 to 2 . Resonant frequency is 600 ~Hz . Change in bandwidth is

Step-by-step solution

Given, f₀=600 ~Hz , Q₁=3, Q₂=2 The bandwidth in L-C-R circuit, = f₀ Q As, quality factor decreases, bandwidth increases. This increase in bandwidth is given by = ₂- ₁= f₀ Q₂ - f₀ Q₁ =f₀ ( 1 Q₂ - 1 Q₁ )=600 ( 1 2 - 1 3 )=100 ~Hz