In a helium ion, if potential energy of electron in ground state is assumed to be zero, then its energy in first excited state is equal to

Step-by-step solution

Potential energy of a He ⁺ ion in ground state is aligned & U₁=2 E₁=2 (-13.6 Z^2 n^2 ) & n=1 and Z=2 & U₁=-108.8 eV aligned But PE in ground state is given zero. So, we have to increase PE (and total energy) by 108.8 eV . Hence, for given He ⁺ ion, energy of first excited state (n=2) will be aligned E(n=2) & =-13.6 Z^2 n^2 +108.8 & =-13.6 4 4 +108.8 & =95.2 eV aligned