If an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit at level n=2 , emitted radiation has a frequency of ( R= Rydberg's constant and c= velocity of light)

Step-by-step solution

The frequency of the radiation emitted when an electron jumps from an energy level n₂ to n₁ is given by the Rydberg formula: = R c ( 1 n₁^2 - 1 n₂^2 ) Given n₁ = 2 and n₂ = 3 , substitute these values into the formula: = R c ( 1 2^2 - 1 3^2 ) = R c ( 1 4 - 1 9 ) = R c ( 9 - 4 36 ) = 5 R c 36 Answer: 5 R c 36