An electron of an atom transits from n₁ to n₂ . In which of the following maximum frequency of photon will be emitted?

Step-by-step solution

For emission of energy, electron of H-atom must fall from higher energy state to lower energy state. Hence, options (a) and (c) are not possible. In option (b), n₁=2, n₂=1 Energy of emitted photon is given as aligned E^ &=-13.6 Z² ( 1 n₁² - 1 n₂² ) h v^ &=-13.6 Z² ( 1 2² - 1 1² ) v^ &= 13.6 Z² h 3 4 aligned In option (c), n₁=2, n₂=6 , hence energy of emitted photon is given as aligned & E^ =-13.6 Z² ( 1 6² - 1 2² ) & h v^ =13.6 Z² 8 36 & v^ = 13.6 Z² h 8 36 aligned Hence, from Eqs. (i) and (ii), we get v^ >v^