COMEDK2019PhysicsAtomic Physics
Excitation energy of a hydrogen like ion in its first excitation state is 40.8 eV . Energy needed to remove the electron from the ion in ground state is
Options
- A54.4 eV
- B13.6 eV
- C40.8 eV
- D27.2 eV
Correct answer
A. 54.4 eV
Step-by-step solution
Excitation energy of hydrogen like ion in its first excitation state, E=40.8 eV For the hydrogen like ion, energy in the ground state (n=1) , E= -13.6 Z² n² eV =-13.6 Z² eV Energy in the first excited state, E₂= -13.6 Z² n² = -13.6 Z² 4 Excitation energy, E=E₂-E₁ aligned &= ( -13.6 Z² 4 +13.6 Z² ) eV &=(-3.4+13.6) Z² eV 40.8 eV &=10.2 Z² eV Z² &= 40.8 10.2 Z² &=4 Z &=2 aligned Thus, energy of the electron in the ground state is given as array ll & E₁=-13.6(2)² eV & E₁=-54.4 eV array Hence, the energy needed to remo