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COMEDK2025PhysicsCapacitanceActual

A capacitor of capacitance 4 ~F is charged to a potential of 24 V and then connected in parallel to an uncharged capacitor of capacitance 6 ~F . The final potential difference across each capacitor will be:

Options

  1. A9.6 V
  2. B6.9 V
  3. C8.2 V
  4. D7.4 V

Correct answer

A. 9.6 V

Step-by-step solution

The initial charge Q on the capacitor of capacitance C₁ = 4 F charged to a potential V₁ = 24 V is given by Q = C₁ V₁ . Q = 4 F 24 V = 96 C . When this capacitor is connected in parallel to an uncharged capacitor of capacitance C₂ = 6 F , the total charge Q is redistributed between the two capacitors until they reach a common potential V . The total capacitance of the parallel combination is C_ eq = C₁ + C₂ = 4 F + 6 F = 10 F . Using the principle of conservation of charge, Q = C_ eq V . 96 C = 10 F V . V = 96 C 10

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