A parallel plate capacitor having a dielectric constant 5 and dielectric strength 10^6 ~V ~m ⁻¹ is to be designed with voltage rating of 2 ~kV . The field should never exceed 10 % of its dielectric strength. To have the capacitance of 60 ~p

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A parallel plate capacitor having a dielectric constant 5 and dielectric strength 10^6 ~V ~m ⁻¹ is to be designed with voltage rating of 2 ~kV . The field should never exceed 10 % of its dielectric strength. To have the capacitance of 60 ~pF the minimum area of the plates should be

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Correct answer: D. 2.7 10⁻² ~m ^2

Working electric field: E = 10 % of 10^6 = 10^5 V m ⁻¹ Plate separation: d = V E = 2000 10^5 = 2 10⁻² m C = K ₀ A d A = Cd K ₀ = 60 10⁻¹² 2 10⁻² 5 8.85 10⁻¹² A = 120 10⁻¹⁴ 44.25 10⁻¹² = 1.2 10⁻¹² 44.25 10⁻¹² 2.7 10⁻² m ^2

A parallel plate capacitor having a dielectric constant 5 and dielectric strength 10^6 ~V ~m ⁻¹ is to be designed with voltage rating of 2 ~kV . The field should never exceed 10 % of its dielectric strength. To have the capacitance of 60 ~pF the minimum area of the plates should be

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