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COMEDK2023Morning ShiftPhysicsCapacitanceActual

A capacitor of capacity 2 ~ F is charged upto a potential 14 ~V and then connected in parallel to an uncharged capacitor of capacity 5 ~ F . The final potential difference across each capacitor will be

Options

  1. A6 V
  2. B4 V
  3. C14 V
  4. D8 V

Correct answer

B. 4 V

Step-by-step solution

The initial charge Q on the first capacitor is given by Q = C₁ V₁ . Q = 2 F 14 V = 28 C . When the two capacitors are connected in parallel, the total charge Q is conserved and is shared between the two capacitors. Let V be the common potential difference across the capacitors. Q = (C₁ + C₂) V . Substituting the given values: 28 C = (2 F + 5 F ) V . 28 = 7 V . V = 28 7 V = 4 V . Answer: 4 V

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