How many 6 F , 200 ~V condensers are needed to make a condenser of 18 F , 600 ~V ?

Step-by-step solution

We know that, in series combination of capacitors, net potential difference is equal to sum of the individual potential difference of each capacitor i.e., V=V₁+V₂+V₃ . . [V₁=V₂=V₃=200 ~V ] 600=n 200 n=3 So, there should be 3 capacitors in series to obtain the required potential difference. The equivalent capacitance of 3 capacitors in series is given as 1 C_ eq = 1 6 + 1 6 + 1 6 = 3 6 = 1 2 C_ eq =2 F Now, we require 18 u capacitance for this, we need 9 number of such capacitors in parallel. Total number of capacit