COMEDK2017PhysicsCapacitance
An air filled parallel plate condenser has a capacity of 2 pF . The separation of the plates is doubled and the interspace between the plates is filled with wax. If the capacity is increased to 6 pF , then the dielectric constant of wax is
Options
- A2
- B3
- C4
- D6
Correct answer
D. 6
Step-by-step solution
Given, capacitance of air filled parallel plate capacitor, C₀=2 pF =2 10⁻¹² ~F ₀ A d =2 10⁻¹² ~F ...(i) When the separation between the plates is doubled, i.e., d^ =2 d And wax of dielectric constant k is filled between the plates of capacitor, then, aligned C^ &=6 pF ₀ k A d^ &=6 10⁻¹² ~F aligned ₀ k A 2 d =6 10⁻¹² [ d^ =2 d ] ₀ A d k 2 =6 10⁻¹² 2 10⁻¹² k 2 =6 10⁻¹² [from Eq . (i)] k=6